From the chart we have
D10 = 0.2
D30 = 0.45
D60 = 1.20
Coefficient of uniformity is = D60/D30
Cu = 1.20/0.2 = 6.0
Coefficient of curvature of the soil is = D302/(D10 x D60)
Cc = 0.452/(0.2 x 1.2)
From the particle size distribution chart we can see that the particles are distributed over a wide range. So, this is a well graded soil.
3 (a) At 0 m Total stress= ?= ?d hw +q = 16 (0) + 10 =10 Kpa Pore pressure = u = ?w x (h – hw) = 9.81 (0)=0 Effective stress = ?’= ? – u = 10 – 0 =10 Kpa At 1 m Total stress= ?= ?d hw +q = 16 (1) + 10 = 26 Kpa Pore pressure = u = ?w x (h – hw) = 9.81 (0) = 0 Effective stress = ?’= ? – u = 26 – 0 = 26 Kpa At 3 m Total stress= ?= ?d hw +q + ?sat (h – hw) = 16 + 10 + 20 (2) = 66 KPa Pore pressure = u = ?w x (h – hw) = 9.81 x (2) = 19.62 Kpa Effective stress = ?’= ? – u = 66 – 19.62 = 46.38 Kpa At 7 m Total stress= ?= ?d hw +q + ?sat (h – hw) = 16 + 10 + 20 (6) = 146 KPa Pore pressure = u = ?w x (h – hw) = 9.81 x (6) = 58.86 Kpa Effective stress = ?’= ? – u = 146 – 58.86 = 87.14 Kpa (b) Unit weight of silty sand = ?s= porosity * specific gravity * 9.81 = 0.54 x 2.61 x 9.81 = 14 kN/m3 Saturated weight of clay =?c= = = 17.82 kN/m3 At 0 m Total stress= ?= ?s h = 14 (0) = 0 Pore pressure = u = ?w x (h – hw) = 9.81 (0) =0 Effective stress = ?’= ? – u = 0 At 2.5 m Total stress= ?= ?s h = 14 (2.5) = 35 KPa Pore pressure = u = ?w x (h – hw) = 9.81 x (0) = 0 Effective stress = ?’= ? – u = 35 - 0 = 35 Kpa At 5 m Total stress= ?= ?s h = 14 x 5 = 70 Kpa Pore pressure = u = ?w x (h – hw) = 9.81 x (2.5) = 24.5 kPa Effective stress = ?’= ? – u = 70 – 24.5 = 45.5 Kpa At 9 m Total stress= ?= ?s h +?c (h – 5) = 14 x 9 + 17.82 (4) = 197.3 KPa Pore pressure = u = ?w x (h – hw) = 9.81 x (6.5) = 63.76 Kpa Effective stress = ?’= ? – u = 197.3 – 63.76 = 133.54 Kpa Question No. 4 (a) Shear box apparatus The soil is contained in a box which has a separate top half and bottom half. A normal stress is
This paper aims to study the Soil Mechanics. In it you may find the particle size distribution curve…
Prestressing is normally accomplished in 3 ways which are: pre-tensioned concrete, followed by bonded and the unbonded and post-tensioned concrete.Pre-tensioned concrete is then cast all around the already tensioned tendons. The pickled concrete sticks to and also ties itself with the bars.
6 Michael Majchrzak, Marshall Lew, Ken Sorensen, Tom Farrell (April 2004). Settlement of Shallow Foundations Constructed Over Reinforced Soil: Design Estimates vs. Measurements. Proceeding: Fifth international conference on case histories in Geo Technical Engineering, New York.
The author of this paper gives full answers on the test on Math. After every question, the full solution is attached.The author completed the exercises where it was needed to find the output levels of the firm that and confirm that the output levels found do indeed maximise or minimise these functions.
The amount of air and water within a sample of soil affects its behavior. The sizes and types of particles that constitute a particular soil affect its properties and thus its load-carrying ability and compressibility. However the soil we find is hardly perfect for any kind of construction before any steps are taken to harden the soil.
If we read the history of Pythagoras we would come to know his influence upon other philosophers like Plato's whole theory is very much affected by his thinking about geometry. He develops it in books VI and VII of the Republic, and says that "what we are talking about in geometry and mathematics, which are generally abstract entities of timeless, spaceless, and impersonal theologies.
There are several laboratory tests more often performed in order to determine different characteristics of soils. These characteristics are important when it comes to designing the foundation and earth structures. This paper focuses on
Water-logging would effectively lead in to swelling of the surrounding soils and thus push the block down. Design of holes in between the retaining is very important to allow for reduction in the water held in the nearby soil. Usually, the design and inherent
As such, the maximum shear stress, which the soil can bear, gives the shear strength of the soil. Excess shear stress results in the failure of the soil, which may occur mostly because of catastrophic loading on the
3 pages (750 words)Assignment
Hire a pro to write a paper under your requirements!
Win a special DISCOUNT!
Put in your e-mail and click the button with your lucky finger
Apply my DISCOUNT
Got a tricky question? Receive an answer from students like you!Try us!
Let us find you an essay for FREE
Contact us via Live Chat, call us at +16312120006or send an email to firstname.lastname@example.org