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# 24-1 - Assignment Example

## Extract of sample 24-1

Particle of matter move continuously. Particles of matter attract each other. Particle of mater has space between them.
(2.9). It is used to compute moments, magnetic fields direction and loosen screws .it is a form of mnemonics used to understand physics. Such can be done by holding both hands together; palm up with the fingers curled for the curl of fingers representing a rotation following the axis consecutively one after the other along the right thumb or left.
(2.10). The magnetic force usually acts at right angles to the charges motion thus the magnetic force cannot work on the charge. The B field at that instance either speed up or slow down the moving charge and only change the direction the charge is moving. The path taken by moving charge in a constant magnetic field is that described by helix with its parallel axis to the direction of the magnetic field (Tipler 477).
2.11. Cauchys equation gives the relation between the refractive index and wavelength of light. The equation provides an empirical relationship that occurs in the refractive index and wavelength of light for a particular transparent material.
(4.1). Given values are V=3.5v, using hc/ ħ=Ø+Vq. Make q subject of the equation. Ø=hc/ ħ-vq.{(6.64*10^(-34)*3.0*10^8)/4.5*10^(-7)m}={4.426*10^(-27)- (0.35*1.6*10^(-19)}=2.766*10^8v-1v=2.765*10^8v but W=-eØ-Ef={(- 1.6*10^(- 19)*2.766*10^8)-0.56*10^(-19)v}=-4.44256*10^(-11)- 0.56*10^(-19)v={- 4.4425*10^-11/1.6*10^(-19)}=2.7765*10^8Joules.
(4.2). Momentum (p)=hf/c or h/ħ, Also E=hf or hc/ ħ, whereby E=25eV, h=6.64*10^-34., c=3.0*10^8m/s. ħ=hc/E={(6.64*10^(- 34)*3.0*10^8)/25eV}=0.7968*10^(-26)m. but p=h/ ...Show more

## Summary

ħ ={ c/f}={(3.0*10^8/5.0*10^15 Hz}=0.6*10^- 7m, but One Argstrong unit =10^(-10m)=600 Angstrong.
(2.7). Waves transfer energy. Energy is the ability to do work. Waves…
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