Mathematical Problem - Lab Report Example

1. From the other car’s reference frame, our car is moving at a constant speed of;

Our car was travelling at a constant speed hence its acceleration from the other car’s frame of reference is zero. The other car will also have an acceleration of zero as measured from our car’s reference frame. The reason is that both cars did not accelerate hence the car will be moving at a constant speed of -20km/hr as observed from our car.

2. a) Since the large box is not moving, the net force between me and a large box is zero hence the magnitude of force between me and the box are equal and opposite.
3. b) The second box, however, is much lighter and does not accelerate the magnitude of the force between me and this second box hence is still equal and opposite. This produces zero net force.
4. c) In this third case. Hence, there is a net force produced. This implies that the force I applied to the box is greater than the force the smaller box applied to me.
5. According to Newton’s second law of motion;

Hence, the acceleration of the cart is produced by a net force of;

The difference between the applied force and the net force is the force of friction, i.e.

The friction force always acts to oppose the motion hence it acts in the opposite direction to the applied force.

4. According to Newton’s first law, since the body keeps changing direction, there must be a force acting on it. An object moving around a circular path at a constant velocity experiences an acceleration towards the center of the circle. According to Newton’s second law, an accelerating body experiences a net force toward the direction of acceleration. This means that the body is experiencing a net force towards the center. According to Newton’s third law, action and reaction forces are equal and opposite. This applies in a circular motion in that to avoid skidding away; the centripetal force must be equal to the friction force on the car tires.