The theoretical y-intercept in the standards equation of a straight line compares (corresponds) to the determined value of T2. The slope (constant) is normally represented by the value of m in the standards equation of a straight line and in this case corresponds to K d.
c. Again, compare the standard form of the equation for a straight line and the result for part (a), what should the theoretical value for the y-intercept be in terms of constants and the dynamical spring constant k d and m0 the effective mass of the spring? In terms of the y-intercept (and other known values), what is the value of the effective mass of the spring m0?
As argued above, the standard equation of a straight line is y= mx +c. This equation implies that y is the same as c since it is the value where the line cuts the y-axis. C is the intercept on the y-axis.
In comparison, if T2 compares to y, and T2=1.61, then it means that the straight line of the graph of T2 against m cuts the x-axis at 1.61. This value depends on the constant K d, since the spring constant results from the resultant forces applied on the spring, the restoring force and the mass, mo applied on the