The Velocity of a Galaxy - Assignment Example

Vr = CZ
C which is considered to be the speed of light is 300,000 Km/s and Z is the redshift respectively.
To find the Redshift, the fraction of the two wavelength ratios must be considered.
This is shown in the below calculations.
Z = (Wavelength- Rest Wavelength)/ Rest Wavelength)
Therefore the Velocity is,
300,000 X (Wavelength- Rest Wavelength)/Rest Wavelength)
a) Galaxy I has a Wavelength of 8204 and the Rest Wavelength of 6563. Therefore, the calculation of the Radial velocity will be;
300,000 Km/s (8204-6563)/6563
= 75011.4277 Km/s
b) Galaxy II has a wavelength of 6549 and the Rest Wavelength of 6563. Therefore, the calculation of radial velocity will be as follows;
300,000 Km/s (6549-6563)/6563
= -639.95124 Km/s


2. Concerning particle interaction, the following reactions must take place;
Conservation of energy takes place in the process of the interactions thus involving the momentum aspect. Besides, the conservation of charge takes place together with the Lepton and the Baryon number. A strong interaction between the weak particles occurs hence making the process of annihilation take place that involves a proton and an antiproton. For one anti-up and up quark to take place, annihilating which is responsible for producing energy is examined.
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4. In relevance to the top-down structure formation, the scenario first forms the large pancakes then followed by the fragment that forms the lumps which are sized. The scenario is important because of the information concerning the existence of large sheets with low density. In respect to the bottom-up structure scenario, there occurs a formation of the galaxies which are small and dwarfs first, followed by the formation of the clusters. Read More