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Quadratic Equations - Assignment Example

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To keep a pet one must possess patience and a passion for the pet that one is raising. Space is vital for the provision of an enabling environment for the rearing of pet. Different pets need different amounts of space for the provision…
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Quadratic Equations
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Quadratic Equations Introduction Raising a pet is not as easy as it looks. To keep a pet one must possess patience and a passion forthe pet that one is raising. Space is vital for the provision of an enabling environment for the rearing of pet. Different pets need different amounts of space for the provision of enough areas for their survival. My pet is a cat, which naturally spends a better part of its day in the house.This does not make it “a potato couch” and; thus, the need to fence my backyard arises.

The backyard is of a rectangular shape with its length, L = 2W- 2 and a width W=13-L. All these measurements are in meters. This area encompasses the whole of my backyard, and it is large enough to provide an ample space the pet. To calculate the area of the rectangle that forms my backyard, the use of quadratic equations is vital.AreaAs aforementioned, the length is 2W-2, and the width is W= 13-L; therefore, we can rearrange the equations as follows:L=2W-2L=13-W, equating the two together a quadratic equation that solves determines the value of one of the unknowns is formed.

13-W=2W-215=3W5=WUsing the value of W, one can determine the value of L and subsequently the area of the backyard.To solve for L: L= 2*5-2 =8 mThe area of a rectangle is determined using the relationship Area= Length*Width (Sterling, 2010). Using this relationship, the area covered by the backyard will be:A=8*5=40sqmPerimeterThis area needs to be fenced in order to keep the pet safe. The materials to be used for the fencing will be determined by the perimeter of the backyard.

The perimeter of a rectangle is determined by the relationship P=2l + 2w (Authors, 2009). The perimeter of the backyard will be P= 2*8 + 2*5=26M using this relationship.This means that some wire netting of 26 meters in length and fourteen posts at an interval of 2 meters will be required to fence the whole backyard. The wire netting will cost $400 while the 14 posts will cost a total of $380. ReferencesAuthors, T. (2009). ADD.Mathematics Form 4. Pelangi Publishing Group Bhd.Sterling, M. J. (2010). Algebra I For Dummies.

New York: John Wiley & Sons.

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