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# The Centrifugal Force - Assignment Example

## Extract of sample The Centrifugal Force

Problem 1 Taking this equation for distance travelled x=vt= 150*30 = 4500 πr/2=4500r=2866.24 m magnitude of centripetal acceleration = v^2/r = -150*150/2866.24 = -7.85 m/s2 The direction will be south at the beginning then north at the end. 2. a. b. The student will feel light. The centrifugal force acts on the student radially outwards when the Ferris wheel spins. At the highest point, this force acts against the weight, hence the student will feel light c. At the highest point, this force acts against the weight, reducing it from 667N to 556 N, So it has magnitude of 667-556=111 N This will act downwards at the lowest point, adding to the weight at the lowest point, So W= 667+ 111 = 776 N d. centrifugal force = mv^2 / r, doubling the velocity will make us have 2^2 = 4 times Hence we will have 4 times centripetal force Maginute = 111*4 = 444 N ...Show more

## Summary

The potential energy will decrease while the kinetic energy will be increasing • A crate crest at the bottom of an inclined plane There is no change in either the kinetic energy or potential energy • …
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